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To find the value of x in the equation (2x + 5 = 10), first subtract 5 from both sides: (2x = 5). Next, divide both sides by 2: (x = \frac{5}{2}) or (x = 2.5). Thus, the value of x is 2.5.
To solve for ( x ) in the equation ( 4bx - 5 = 5c ), first add 5 to both sides to get ( 4bx = 5c + 5 ). Then, divide both sides by ( 4b ) to isolate ( x ): [ x = \frac{5c + 5}{4b}. ] Thus, the value of ( x ) is ( \frac{5(c + 1)}{4b} ).
To find what you divide 5 by to get 11, you can set up the equation ( \frac{5}{x} = 11 ). Solving for ( x ), you multiply both sides by ( x ) and then divide by 11, resulting in ( x = \frac{5}{11} ). Thus, you divide 5 by ( \frac{5}{11} ) to get 11.
y = 2x+5 x+y = 4 Substitute the value of y into the second equation: x+2x+5 = 4 x+2x = 4-5 3x = -1 Divide both sides by 3 to find the value of x: x = -1/3 Substitute the value of x into the original equations to find the value of y: x = -1/3 and y = 4 and 1/3
The quotient of 12 and 5 times a number can be expressed mathematically as ( \frac{12}{5x} ), where ( x ) represents the number. This means you divide 12 by the product of 5 and the chosen number ( x ). The result gives you a value that depends on the specific value of ( x ).
5 x 163 = 815
To find a factor that can divide the product of 815 and 516, we can first determine their prime factorizations. The number 815 can be factored into 5 × 163, while 516 can be factored into 2 × 3 × 43. The common factor that divides both numbers is 1, but for a non-trivial factor, we can consider the individual prime factors of either number. Thus, a factor that can divide 815 × 516 is 1, or any of their prime factors like 5, 2, or 3.
815 o F is the answer. celsius x 9, divided by 5, plus 32. 435x9=3915, 3915/5=783, 783+32=815 degrees fahrenheit OR, (celsius x 1.8) + 32 EX: (435 x 1.8) + 32 = 815
To find the value of x in the equation (2x + 5 = 10), first subtract 5 from both sides: (2x = 5). Next, divide both sides by 2: (x = \frac{5}{2}) or (x = 2.5). Thus, the value of x is 2.5.
10% x 815 = 81.5
To solve for ( x ) in the equation ( 4bx - 5 = 5c ), first add 5 to both sides to get ( 4bx = 5c + 5 ). Then, divide both sides by ( 4b ) to isolate ( x ): [ x = \frac{5c + 5}{4b}. ] Thus, the value of ( x ) is ( \frac{5(c + 1)}{4b} ).
5x+5 = 20 Subtract 5 from both sides: 5x = 15 Divide both sides by 5 to find the value of x: x = 3
8x + 5 = 25(- 5 from both sides)8x = 20(divide both sides by 8)x = 2.5
3x + 7 = 22 Subtract '7' from both sides Hence 3x = 15 Divide both sides by '3' x = 5 The answer !!!
To find what you divide 5 by to get 11, you can set up the equation ( \frac{5}{x} = 11 ). Solving for ( x ), you multiply both sides by ( x ) and then divide by 11, resulting in ( x = \frac{5}{11} ). Thus, you divide 5 by ( \frac{5}{11} ) to get 11.
remember: ''is value'' over ''of value'' equals ''%'' over ''100'' is/of = %/100 --------> x/3,000,000 = 5%/100 (cross cancel)100x = 15,000,000 ( divide both by 100 to get x by itself)x = 150,000
y = 2x+5 x+y = 4 Substitute the value of y into the second equation: x+2x+5 = 4 x+2x = 4-5 3x = -1 Divide both sides by 3 to find the value of x: x = -1/3 Substitute the value of x into the original equations to find the value of y: x = -1/3 and y = 4 and 1/3