The value in cents of ( d ) dimes can be calculated by multiplying the number of dimes by 10, since each dime is worth 10 cents. Therefore, the value is ( 10d ) cents. For example, if there are 5 dimes, the value would be ( 10 \times 5 = 50 ) cents.
Let the Number of Dimes be D, then the number of nickels = 73 - DBy value, 5(73 - D) + 10D = 580 : 365 - 5D + 10D = 580 : 5D = 215 : D = 43There are 43 dimes.
6 dimes have a face value of 60 cents.
60 cents
Nickels are worth five cents and dimes are worth ten.
Let ( q ) be the number of quarters and ( d ) be the number of dimes. We have two equations based on the problem: ( q + d = 102 ) (the total number of coins) ( 25q + 10d = 1710 ) (the total value in cents) Solving these equations, we find that there are 6 quarters and 96 dimes.
Let the Number of Dimes be D, then the number of nickels = 73 - DBy value, 5(73 - D) + 10D = 580 : 365 - 5D + 10D = 580 : 5D = 215 : D = 43There are 43 dimes.
6 dimes have a face value of 60 cents.
9 dimes are worth 90 cents.
60 cents
Five dimes are worth 50 cents, as each dime is worth 10 cents. Therefore, you can calculate the total value by multiplying the number of dimes (5) by the value of each dime (10 cents).
Nickels are worth five cents and dimes are worth ten.
Let ( q ) be the number of quarters and ( d ) be the number of dimes. We have two equations based on the problem: ( q + d = 102 ) (the total number of coins) ( 25q + 10d = 1710 ) (the total value in cents) Solving these equations, we find that there are 6 quarters and 96 dimes.
9 dimes are worth 90 cents.
1.05
Unless it's silver it's worth 10 cents. D and P mintmarks are not silver.
5 dimes is 5 x 10 cents = 50 cents. 3 nickels is 3 x 5 cents = 15 cents. 50 cents + 15 cents = 65 cents.
80 cents one-third of six is two, so two dimes is 20 cents if one-fourth is 20 cents then her total amount is 80 cents