3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
2/12 + 2/12 + 4/12 + 9/12 + 6/12 = 23/12 or 1 and 11/12
The sum of 11/12 and 2/3 = 1 7/12
149
3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
2/12 + 2/12 + 4/12 + 9/12 + 6/12 = 23/12 or 1 and 11/12
The sum of 11/12 and 2/3 = 1 7/12
11 plus 2 is 1 when calculating in modulo 12.
149
If 3x - 1 = 11 what is the value of x 2 + x?
8/12 + 3/12 = 11/12
It is; 1/4 plus 2/3 = 11/12
12
The value of x is 2
x2 + 12x - 11 = x2 + 12x + (12/2)2 - (12/2)2 - 11 = (x + 6)2 - 47