4a+3a-4 = 10 4a+3a = 10+4 7a = 14 a = 2
a= -4
4a+5=25 4a=25-5 4a=20 a=20/4 a=5
4a + 2 = Answer let a = 2 then Answer equals 4(2) + 2 = 8 + 2 = 10.
4a+3 when a=34(3)+312+3=15So you are substituting(replacing) 'a' with the known value of '3'. You then multiply the '4' with the '3' because of the placing of 'a'.
9=4a+13 9-13=4a -4=4a -4/4=a -1=a a=-1
555
4a+3a-4 = 10 4a+3a = 10+4 7a = 14 a = 2
the answer is 52 because what plus four gives you 56 it is 52. 52+4=56
a= -4
4a+5=25 4a=25-5 4a=20 a=20/4 a=5
4a + 2 = 4(6) + 2 = 24 + 2 = 26
4a + 2 = Answer let a = 2 then Answer equals 4(2) + 2 = 8 + 2 = 10.
4a+3 when a=34(3)+312+3=15So you are substituting(replacing) 'a' with the known value of '3'. You then multiply the '4' with the '3' because of the placing of 'a'.
2a*3 = 8+4a 6a = 8+4a 6a-4a = 8 2a = 8 a = 4
a + 4 = 10(a + 4) - 4 = 10 - 4a = 6
It is an equation in the single unknown variable, a. a = -4