(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
sqrt(-752) = 4i sqrt(47) i = sqrt(-1)
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
7
('|x|' = Absolute value of x) |3+4i| = √(32 + 42) = √(9+16) = √25 = 5 Thus |3+4i| = 5.
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
-6-4i.
(x - 4i)(x + 4i) where i is the square root of -1
-9
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
1
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
To get the conjugate simply reverse the sign of the complex part. Thus conj of 7-4i is 7+4i
Add the real and the imaginary parts separately.
-4, +4, -4i and 4i