5 - 5/3 + 5/9 - 5/27 + ... = 5 + 5(-1/3)¹ + 5(-1/3)² + 5(-1/3)³ + ...
The required sum is an infinite GP with initial term a = 5, and common difference r = -1/3
As |r| < 1, the sum can be found from sum = a/(1 - r)
→ 5 - 5/3 + 5/9 - 5/27 + ...
= 5/(1 - (-1/3))
= 5/(1 + 1/3)
= 5/(4/3)
= 5 × 3/4
= 15/4
= 3¾
27 times 3 minus 46 plus 23 equals 58.
18/27 minus 44/81 is 10/81
X=27
2/9 minus 5/27 = 1/27
It is: -73--27 = -46 because a double minus becomes a plus and --27 is the same as +27
27 times 3 minus 46 plus 23 equals 58.
18/27 minus 44/81 is 10/81
X=27
2/9 minus 5/27 = 1/27
It is: -73--27 = -46 because a double minus becomes a plus and --27 is the same as +27
27. 2+7=9 then minus 4. Next is plus 8 minus 3. Plus 9 minus 2. Plus 10 (27). Next is minus 1 which would be 26.
4188.5
43 minus 27 3/7 = 15 4/7
51 minus 27 3/7 = 23 4/7
-2x -11y - 13
21
9