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The value of (8C4) is calculated using the formula for combinations, which is (nCr = \frac{n!}{r!(n-r)!}). For (8C4), this becomes:

[ 8C4 = \frac{8!}{4!(8-4)!} = \frac{8!}{4! \times 4!} = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} = 70 ]

Thus, (8C4 = 70).

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The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.


What is the probability of a family that has 8 children 4 of them are girls?

For any particular pair of parents, the gender of their children is not 1/2 nor are the genders independent. However, if you assume that they are, and that the probability of either gender is 0.2, the probability tat 4 out of 8 are girls is 8C4*(1/2)8 = 70/256 = 0.27 approx.


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Question is not very clear about the context of word 'sequence' here. If I am to select 4 numbers out of four and arrange them in order then there are 4!*8C4 = 1680 different sequences possible. If the word sequence refers to some arithmetic sequence or geometric sequence, then counting is going to change for sure.


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Oh, what a lovely question! You see, when we have 8 numbers and we want to choose 4 of them, we can use a special formula called combinations. The number of combinations we can make is calculated using the formula 8! / (4! * (8-4)!), which simplifies to 70 combinations. Isn't that just delightful? Just imagine all the beautiful possibilities waiting to be created!


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Related Questions

How many four number combinations are there in the numbers 1 through 8?

The answer is 8C4 = 8*7*6*5/(4*3*2*1) = 70


How many 4 number combinations using 2 3 4 5 6 7 8?

The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.The number of combinations of 4 numbers out of 8 is 8C4= (8*7*6*5/(4*3*2*1) = 70.In a combination, the order of the numbers does not matter so that 2345, 2454, 4523 etc are all counted as 1.


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For any particular pair of parents, the gender of their children is not 1/2 nor are the genders independent. However, if you assume that they are, and that the probability of either gender is 0.2, the probability tat 4 out of 8 are girls is 8C4*(1/2)8 = 70/256 = 0.27 approx.


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Question is not very clear about the context of word 'sequence' here. If I am to select 4 numbers out of four and arrange them in order then there are 4!*8C4 = 1680 different sequences possible. If the word sequence refers to some arithmetic sequence or geometric sequence, then counting is going to change for sure.


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Oh, what a lovely question! You see, when we have 8 numbers and we want to choose 4 of them, we can use a special formula called combinations. The number of combinations we can make is calculated using the formula 8! / (4! * (8-4)!), which simplifies to 70 combinations. Isn't that just delightful? Just imagine all the beautiful possibilities waiting to be created!


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