(b+h)(b+h)= b2+2hb+h2.
h, being the step size of an algorithm in numerical analysis, is always (b-a)/N where x is in the interval [a, b] and N is the number of iterations in the algorithm.
B = 2H - 3; (B x H)/2 = 10 ie B x H = 20;2H2 - 3H - 20 = 0(H - 4)(2H + 5) = 0Only positive value for H is 4, making B = 5 cm
b/h
You cannot. If the base is B and the height is H any of the following will give an area of 13: B = 13, H = 1 B = 130, H = 0.1 B = 1300, H = 0.01 etc. Or, B = 6.5, H = 2 B = 65, H = 0.2 etc Or B = 2.6, H = 5 B = 26, H = 0.5 etc I hope you get the idea.
an estimate of 7,000 to 12,000
(b+h)(b+h)= b2+2hb+h2.
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h, being the step size of an algorithm in numerical analysis, is always (b-a)/N where x is in the interval [a, b] and N is the number of iterations in the algorithm.
The average value of a function is the equivalent area of the function expressed like a rectangle .- Thus If you have an area A from limits a and b , the equivalent is : (b-a) H ( rectangle area ) = INT f(x) dx , then average H is H= ( INT f(x) dx) /(b-a)
B = 2H - 3; (B x H)/2 = 10 ie B x H = 20;2H2 - 3H - 20 = 0(H - 4)(2H + 5) = 0Only positive value for H is 4, making B = 5 cm
b/h
There is no figure given!!!! However, In a triangle the three angles are A B & 90 degrees. The sides opposite to A,B, & 90 are 'a' , 'b' & 'h' respectively. Hence Sin A = a/h SinB = b/h CosA = a/h ( Check ; 'a/h') Csc B ( CosecantB) = 1/ (a/h) = h/a CotB = CosB / SinB = (a/h) / (b/h) = a/b
The equation for the area of a triangle goes as followed: A = [(b)(h)]/2 A = Area b = base h = height Your known values are A = 30 h = 10 Unknown values b = ? Simply plug in your known values to find your unknown value: 30 = [(b)(10)]/2 (30)(2) = (b)(10) 60 = (b)(10) (60)/(10) = b b = 6
If an additional B is added to the reaction, the reaction will be more likely to proceed towards completion, as there will be more B molecules available to react with KL and H. This may lead to an increase in the amount of product formed, depending on the stoichiometry and conditions of the reaction.
You cannot. If the base is B and the height is H any of the following will give an area of 13: B = 13, H = 1 B = 130, H = 0.1 B = 1300, H = 0.01 etc. Or, B = 6.5, H = 2 B = 65, H = 0.2 etc Or B = 2.6, H = 5 B = 26, H = 0.5 etc I hope you get the idea.
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b