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What is the value of h if the point h 0 is equidistant from the points -1 7 and -3 -2?
Let A = (-1, 7), B = (-3, -2) and C = (h, 0).
Then |AC| = |BC|
AC2 = BC2
so (h + 1)2 + (0 - 7)2 = (h + 3)2 + (0 + 2)2
or h2 + 2h + 1 + 49 = h2 + 6h + 9 + 4
so that 4h = 37
therefore h = 37/4 = 9.25
Further Information:
The outline is in the form of an isosceles triangle and the 1st answer is correct because the point (9.25, 0) is equidistant from the points (-1, 7) and (-2,-3)
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