To find the value of the function ( f(6) = 32x - 12 ) when ( x = 6 ), substitute 6 for ( x ):
[ f(6) = 32(6) - 12 = 192 - 12 = 180. ]
Thus, the value of the function when ( x = 6 ) is 180.
3
2*abs(-6) = 2*6 = 12
The expression appears to be: (12-4t)/6
If the table defines the function f, then the answer is f(6).
To find the range of the function ( f(x) = 12 - 3x ) for the given domain values of ( x = -4, -2, 0, 2, 4 ), we can calculate ( f(x) ) for each value: ( f(-4) = 12 - 3(-4) = 24 ) ( f(-2) = 12 - 3(-2) = 18 ) ( f(0) = 12 - 3(0) = 12 ) ( f(2) = 12 - 3(2) = 6 ) ( f(4) = 12 - 3(4) = 0 ) Thus, the range of the function for the specified domain is ( {0, 6, 12, 18, 24} ).
Six hundred.
105.3333
3
beause hundred
0
72 in 12 = 6
2*abs(-6) = 2*6 = 12
0.0016
The expression appears to be: (12-4t)/6
Range is the largest minus the smallest value; so 12 - 6 is range of 6.
8
632 written in expanded form is (6*100) + (3*10) + (2*1)