Q: What is the value of x in 4x minus 2 equals 78?

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It is an equation and the value of x is 8

4x + y = 9 so that y = 9 - 4x 7x - 8y = 6 7x - 8*(9-4x) = 6 7x - 72 + 32x = 6 39x = 78 x = 2 Then y = 9 - 4x = 9-4*2 = 9-8 = 1

The diagonals will be equal and so: 4x-47 = 2x+31 => 4x-2x = 31+47 => 2x = 78 Therefore the value of x is: x = 78/2 => x = 39

x = number Four times the number (4x) is the same as the number increased by 78 (x + 78). Since they are both equal, then 4x = x + 78 4x - x = 78 3x = 78 x = 26

1516 - 78 = 1438

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It is an equation and the value of x is 8

To solve the equation "4x = 78" for x, you would divide both sides by 4. This gives you x = 78 รท 4, which simplifies to x = 19.5. Therefore, the value of x that satisfies the equation "4 times x equals 78" is 19.5.

4x + y = 9 so that y = 9 - 4x 7x - 8y = 6 7x - 8*(9-4x) = 6 7x - 72 + 32x = 6 39x = 78 x = 2 Then y = 9 - 4x = 9-4*2 = 9-8 = 1

The diagonals will be equal and so: 4x-47 = 2x+31 => 4x-2x = 31+47 => 2x = 78 Therefore the value of x is: x = 78/2 => x = 39

180 degrees minus 102 degrees equals 78 degrees.

x = number Four times the number (4x) is the same as the number increased by 78 (x + 78). Since they are both equal, then 4x = x + 78 4x - x = 78 3x = 78 x = 26

78

6 times 13 equals 78 3 times 26 equals 78 2 times 39 equals 78 and 1 times 78 equals 78

78 - 21 = 57

116 - 78 = 38

161 - 78 = 83

78 - 5.683 = 72.317