Using the quadratic formula, you will find for the equation 6x² + 2x + k = 0:
x = (-b ±√(b² - 4ac)) / 2a
→ x = (-2 ± √(2² - 4×6×k)) / (2×6)
→ x = (-2 ± √(4 - 4×6k)) / (2×6)
→ x = (-1 ± √(1 - 6k)) / 6
The value of the discriminant (b² - 4ac) affects the value of x:
>0 → there are two real values of x; this happens when 1 - 6k > 0 → k < 1/6;
=0 → there is one repeated root, ie a single value of x; this happens when k = 1/6 (making x = -1/6);
<0 → there are two complex values of x; this happens when k > 1/6.
The value of x is 7
Using the discriminant for a quadratic equation the value of k works out as plus or minus 12.
14.2
6 (APEX)
2
The value of x is 7
a=64 b=8 (x+16x+64)=(x+8)^2
Using the discriminant for a quadratic equation the value of k works out as plus or minus 12.
14.2
6 (APEX)
2
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
4 squared is 4 x 4 which equals 16.
Because the value of C equals 13
The equation does not have a real number solution. Using the quadratic formula will give it's conjugate pair complex solution.
64
10 squared means 10*10 which equals 100.