3x-y = 11 x+y = 5 Add both equations together: 4x = 16 Divide both sides by 4 to find the value of x: x = 4 Substitute the value of x into the original equations to find the value of y: Therefore: x = 4 and y = 1
In expressions such as "x-y", both "x" and "y" can have any value. The value of "x-y" will depend on what the value of "x" and the value of "y" are.
Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps! Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps!
Here x is equls to 9 and y is equal to 4
y is a function of x iffor each value of x (in the domain) there is a value of y, andfor each value of y (in the range) there is at most one value of x.
11
Here first, the value of variable is incremented/decremented , then the value of variable is taken for operation. For eg. :- Consider the following statements- 1. x=++y ; ( where y=10 ) After execution, value of x & y is - x=11; y=11; Because first, the value of y is incremented by 1 and then assigned to x.
To find the value of ( y ) when ( x = 11 ), we can substitute ( x ) with 11 in the equation ( 7x - 9y = 23 ) and solve for ( y ): [ 7(11) - 9y = 23 ] [ 77 - 9y = 23 ] [ -9y = 23 - 77 ] [ -9y = -54 ] [ y = \frac{-54}{-9} ] [ y = 6 ] So, when ( x = 11 ), ( y = 6 ).
Here first, the value of variable is incremented/decremented , then the value of variable is taken for operation. For eg. :- Consider the following statements- 1. x=++y ; ( where y=10 ) After execution, value of x & y is - x=11; y=11; Because first, the value of y is incremented by 1 and then assigned to x.
Call the numbers x and y. Then, from the problem statement, x + y = 11 and xy = 36. From the first of these equations, x = 11 - y. Substituting this value into the second equation yields (11 - y)y = 36 or 11y - y2 = 36 or y2 - 11 y + 36 = 0. Use the quadratic equation formula to find y, then subtract that value from 11 to obtain x.
3x-y = 11 x+y = 5 Add both equations together: 4x = 16 Divide both sides by 4 to find the value of x: x = 4 Substitute the value of x into the original equations to find the value of y: Therefore: x = 4 and y = 1
In expressions such as "x-y", both "x" and "y" can have any value. The value of "x-y" will depend on what the value of "x" and the value of "y" are.
Two solutions:x = 5 and y = 6, orx = 6 and y = 5.
Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps! Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps!
2x + y = 25 x + y = 14 Subtract second equation from the first: x = 11 Substitute this value of x in the second equation: 11 + y = 14 ie y = 3
Here x is equls to 9 and y is equal to 4
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