y = 6
As y is inversely proportional to x, the equation relating x to y is given by: y = k/x where k is the constant of proportionality. Using this we can find expressions for the value of y when x = 2 and x = 6 in terms of k: x = 2 → y = k/2 x = 6 → y = k/6 The difference between these is k/2 - k/6 = 3k/6 - k/6 = 2k/6 = k/3 But this, we are told is 5; thus: k/3 = 5 → k = 15 Thus y = 15/x Now that we have found the equation relating x to y, we can plug in the value for x = 4 and find the value of y: The value for y when x = 4 is y = 15/4 = 3.75
3
Assuming 6 refers to the value of x, the y coordinate is 1
In expressions such as "x-y", both "x" and "y" can have any value. The value of "x-y" will depend on what the value of "x" and the value of "y" are.
y = 6
As y is inversely proportional to x, the equation relating x to y is given by: y = k/x where k is the constant of proportionality. Using this we can find expressions for the value of y when x = 2 and x = 6 in terms of k: x = 2 → y = k/2 x = 6 → y = k/6 The difference between these is k/2 - k/6 = 3k/6 - k/6 = 2k/6 = k/3 But this, we are told is 5; thus: k/3 = 5 → k = 15 Thus y = 15/x Now that we have found the equation relating x to y, we can plug in the value for x = 4 and find the value of y: The value for y when x = 4 is y = 15/4 = 3.75
8x = 6y (8/6)x = y (4/3)x = y Let x = 3, 6, and 9, then y = 4, 8, and 12. So that for any value of x, you will find a correspoinding value for y.
y is 2/3.
-6
Two solutions:x = 5 and y = 6, orx = 6 and y = 5.
You already know the value of x is 4. To solve the value of y = 64x, mutlply 64 x 4. Hence, y = 64*4 = 256.
2x+y = 10 x +y = 4 Subtract bottom equation from top equation: x = 6 Substitute the value of x into the equations to find the value of y: x = 6 and y = -2
If this is an inequality (6 is less than x, or 6 < x), then x is an integer or other value greater than 6.---The variable statement "6 less than x" is (x - 6)This is a value (variable and constant) where the value of x is determined by an equationsuch as x-6 = 4 (x is positive 2) or y = x-6 (y is 6 less than x).
you subtract x from both sides for both equations to get it in y= form. so... x+y=5 x+y-x=5-x y=5-x x+y=6 x+y-x=6-x y=6-x thanks:D but i meant with absolute value signs it was supposed to look like this : |x+y|=5 and |x|+|y|=6 ... but when i typed it in answers.com changed it
3
Assuming 6 refers to the value of x, the y coordinate is 1