Put n = 1, 2, 3, 4 etc in the expression 5n + 2 and evaluate to get the sequence.
The variable is d, in the algebraic expression 7d+2
The variable is "d".
5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6
5n-2+2=4n 5n=4n n=0
N
Put n = 1, 2, 3, 4 etc in the expression 5n + 2 and evaluate to get the sequence.
The variable is d, in the algebraic expression 7d+2
The variable is "d".
It is impossible to read exactly what the expression is - it looks like there are some operators missing from expression: between the 2 and 5n, between the 5 and n, between the 3 and n. As written it looks like: 25n + 3 + 5n + 3n + 2 = 33n + 5 which is not divisible by 17 for n = 1 (at least). Please re-ask your question spelling out every operator, eg 2 bracket 5n plus 3 close bracket plus 3 minus n...
5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6
5n-2+2=4n 5n=4n n=0
5n+2n=7n If the variable is the same, n, then you can add the coefficients, 5 and 2. In General an+bn=(a+b)n FOR A CASE THAT DOES NOT WORK. 5n+2m=5n+2m You cannot combine unlike variables
It is either 3*2 + a or 3*(2 + a)
5n - 4 = 10n + 6-5n = 10n = -2
7h - 2 - 51 is an expression NOT an equation. An expression cannot be solved for the value of a variable.
Yes