The variance is: 500.0
10, 10, 20, 30, 30, 50.
V = 50.0
There are two sets of 3 consecutive numbers whose sum is 30 but neither set contains all odd numbers. The two sets are: 8, 10 and 12 as well as 9, 10 and 11.
30 = XXX 10 + 10 + 10
The factors of 30 that are not prime numbers are 6, 10 and 30.
10, 10, 20, 30, 30, 50.
V = 50.0
To answer this question I will use an example. Data set: 10, 20, 30, 40, 50. First find the sum of all the numbers...so 10+20+30+40+50= 150. Then you take the sum (150) and divide it by the number of numbers in the data set. So 150 divided by 5 (the number of numbers in this data set) = 30. 30= the mean of the above data set. Finding the mean is pretty simple. :)
30 belongs to the set of natural numbers
There are two sets of 3 consecutive numbers whose sum is 30 but neither set contains all odd numbers. The two sets are: 8, 10 and 12 as well as 9, 10 and 11.
15 and 30
30 = XXX 10 + 10 + 10
If you are including 10 and 30 there are 11 even numbers. If you are not counting 10 and 30 there are 9 even numbers between 10 and 30.
11, 13, 17, 19, 23, 29 are the primes between 10 and 30 so the composite numbers are all the others. 12,14,15,16,18,20,21,22,24,25,26,27,28, and 30 are the composite numbers between 10 and 30.
The variance of 30 32 47 57 66 and 79 = 371.7667
260
The factors of 30 that are not prime numbers are 6, 10 and 30.