Wiki User
∙ 14y agoIf the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the ground
its velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
Wiki User
∙ 14y agoIgnoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters
7
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
18
593 meters.
The sprinter's velocity at 1.2 seconds can be calculated using the formula: velocity = initial velocity + acceleration × time. Given the initial velocity is 0 m/s, acceleration is 2.3 m/s^2, and time is 1.2 seconds, the velocity at 1.2 seconds would be 2.76 m/s.
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
A .50 cal bullet shot level will typically drop around 350-400 inches (9-10 feet) in a mile due to gravity and air resistance. Factors like muzzle velocity, bullet weight, and atmospheric conditions can affect the exact amount of drop.
The initial acceleration will be about 9.8 meters per second squared (m/s2) and the acceleration gradually drops to zero due to air resistance. The terminal velocity varies greatly for a person curled up into a ball and a person with a parachute.
Well, to answer this you need to find the meters per second. To find that we need to see how many meters the hammer moves in one second. To do this just divide the meters traveled by the seconds taken: 6/2.7 = 2.2222 (repeating) don't be frightened by the repeating 2s this just means that it's a fraction. The number can be changed into: a mixed number: 2 2/9 (That's 2 and 2 over 9) or as a mixed number 20/9 (20 over 9)
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
The duration of Eye Drops is 1800.0 seconds.
Assuming the gasoline has the same approximate drop size as water, there are 20 drops per ml. Therefore 2 drops per second = 120 drops/min = 7200 drops/hr = 172800 drops/day = 1,209,600 drops/wk Divide that by 20000 (drops/liter) gives you about 60.5 liters.
Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters