IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per second
in the direction of the acceleration, at the end of 30 seconds.
-2.33 metres per second squared
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
The change in the velocity divided by time in meters per second squared.
Use the formula for centripetal acceleration: velocity squared / radius.
Seconds are not squared in the acceleration formula. The units for acceleration are meters per second squared (m/s^2), where the time unit (seconds) is squared to represent the change in velocity over time.
Velocity can be measured in metres per second, not metres per second squared. Acceleration is measured in metres per second squared but knowing only the acceleration does not help in finding the velocity.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
-2.33 metres per second squared
The velocity gained by the aircraft in 4 seconds can be calculated using the formula: velocity = acceleration × time. Given acceleration of 3 m/s^2 and time of 4 seconds, the velocity gained by the aircraft would be 12 meters per second.
Acceleration is the rate of change of velocity over time. By dividing a unit of velocity by a unit of time, we can derive the unit of acceleration. For example, if velocity is measured in meters per second (m/s) and time is measured in seconds (s), acceleration would be in meters per second squared (m/s^2).
To determine the velocity of the ball 0.6 seconds after its release, we need more information such as the initial velocity and acceleration of the ball. You would use the formula: velocity = initial velocity + (acceleration * time).
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
Meters/seconds squared
False. The SI unit of velocity is meters per second (m/s), not meters per second squared. Meters per second squared is the unit for acceleration.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
The change in the velocity divided by time in meters per second squared.