2x - 81 = 0 Add 81 to both sides. 2x - 81 + 81 = 0 + 81 Substitute, -81 + 81 cancels out. 2x = 81 Divide by 2. x = 40.5 Above answer would be correct if your question was 2x but it was x2 so using the same method you would get x2 = 81 here the opposite of the square is the square root x = 9
4x2-36x+81 (2x-9)(2x-9)
85
The expression is likely 4x2 - 36x +81 which is the same as (2x - 9)(2x - 9) or (2x - 9)2
(2x - 9)(2x - 9) or (2x - 9)2
4x2 - 36x + 81 = 4x2 - 18x - 18x +81 = 2x(2x - 9) - 9(2x - 9) = (2x - 9)2
If that's + 81, the answer is (2x - 9)(2x - 9) or (2x - 9)2 If that's - 81, it gets ugly in a hurry.
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
2x - 81 = 0 Add 81 to both sides. 2x - 81 + 81 = 0 + 81 Substitute, -81 + 81 cancels out. 2x = 81 Divide by 2. x = 40.5 Above answer would be correct if your question was 2x but it was x2 so using the same method you would get x2 = 81 here the opposite of the square is the square root x = 9
4x2-36x+81 (2x-9)(2x-9)
85
(2x - 3)(2x + 3)(4x2 + 9)
The expression is likely 4x2 - 36x +81 which is the same as (2x - 9)(2x - 9) or (2x - 9)2
(2x - 9)(2x - 9) or (2x - 9)2
(2x - 9)(2x - 9) or (2x - 9)2
(2x - 9)(2x - 9)
4x^(2) - 81 First remember the two numbers are both squared numbers. 4 = 2^(2) & 81 = 9^(2) Hence (2x)^(2) - 9^(2) Next remember two squared terms with a negative(-) between them , will factor. Hence (2x - 9)(2x + 9) Note the two different signs. NB Two squared terms with a positive (+) between them does NOT factor. .