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The vertex of the quadratic function ( f(x) = ax^2 + bx + c ) can be found using the formula ( x = -\frac{b}{2a} ). Once you determine the x-coordinate of the vertex, you can substitute it back into the function to find the corresponding y-coordinate. Therefore, the vertex is at the point ( \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right) ). If the function is given as ( f(x) = x^2 + c ) (where ( a = 1 ) and ( b = 0 )), the vertex simplifies to ( (0, c) ).

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7h ago

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