The vertex of the quadratic function ( f(x) = ax^2 + bx + c ) can be found using the formula ( x = -\frac{b}{2a} ). Once you determine the x-coordinate of the vertex, you can substitute it back into the function to find the corresponding y-coordinate. Therefore, the vertex is at the point ( \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right) ). If the function is given as ( f(x) = x^2 + c ) (where ( a = 1 ) and ( b = 0 )), the vertex simplifies to ( (0, c) ).
A common technique to rewrite a quadratic function in standard form ( ax^2 + bx + c ) to vertex form ( a(x - h)^2 + k ) is called "completing the square." This involves taking the coefficient of the ( x ) term, dividing it by 2, squaring it, and then adding and subtracting this value inside the function. By rearranging, you can express the quadratic as a perfect square trinomial plus a constant, which directly gives you the vertex coordinates ( (h, k) ).
It is (1, 1).
It is a quadratic function which represents a parabola.
The vertex is at the point (0, 4).
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
It is (1, 1).
The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.
It is a quadratic function which represents a parabola.
The vertex is at the point (0, 4).
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
A quadratic function is a function where a variable is raised to the second degree (2). Examples would be x2, or for more complexity, 2x2+4x+16. The quadratic formula is a way of finding the roots of a quadratic function, or where the parabola crosses the x-axis. There are many ways of finding roots, but the quadratic formula will always work for any quadratic function. In the form ax2+bx+c, the Quadratic Formula looks like this: x=-b±√b2-4ac _________ 2a The plus-minus means that there can 2 solutions.
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
(1/2, 71 and 3/4)or(0.5, 71.75)
x = -3y = -14
The given equation is not that of a parabola.
put it into the quadratic formula: for ax2+bx+c=0 x= - b (plus or minus)rad(b2-4ac) 2a