Volume= 4/3 * pi * r^3 (where * means multiply and ^3 means cubed
So for a sphere of radius 9 Vol = 4/3 * pi * 729 = pi * 972 = 3,053.628 cubic units.
Surface area = 4 * pi * r^2 (where ^2 means squared
So for a sphere of radios 9, the SA = 4 * pi * 81 = pi * 324 = 1017.876 square units
Given a sphere of radius r, Surface area = 4{pi}r2 Volume = (4/3){pi}r3
Volume = 4/3 * pi * radius * radius * radius Surface Area = 4 * pi * radius * radius
Let the radius of the sphere be r. surface area of the sphere = 4 * pi * r^2 volume = (4 * pi * r^3)/3
Impoved Answer:-Surface area of a sphere: 4*pi*radius squaredVolume of a sphere: 4/3*pi*radius cubed
Surface area to volume ratio in nanoparticles have a significant effect on the nanoparticles properties. Firstly, nanoparticles have a relative larger surface area when compared to the same volume of the material. For example, let us consider a sphere of radius r: The surface area of the sphere will be 4πr2 The volume of the sphere = 4/3(πr3) Therefore the surface area to the volume ratio will be 4πr2/{4/3(πr3)} = 3/r It means that the surface area to volume ration increases with the decrease in radius of the sphere and vice versa.
Use the formula for volume to solve for the radius of the sphere and then plug that radius into the formula for the surface area of a sphere.
Given a sphere of radius r, Surface area = 4{pi}r2 Volume = (4/3){pi}r3
If they have the same radius then it is: 3 to 2
Volume = 4/3 * pi * radius * radius * radius Surface Area = 4 * pi * radius * radius
Volume = 113.097 m3 Surface area = 113.097 m2
surface area = 4(pi)(radius)^2 volume = (4/3)(pi)(radius)^3 hope this helped!
Let the radius of the sphere be r. surface area of the sphere = 4 * pi * r^2 volume = (4 * pi * r^3)/3
Impoved Answer:-Surface area of a sphere: 4*pi*radius squaredVolume of a sphere: 4/3*pi*radius cubed
The surface area of a sphere with a radius of 13ft is about 2,123.7ft2
Surface area to volume ratio in nanoparticles have a significant effect on the nanoparticles properties. Firstly, nanoparticles have a relative larger surface area when compared to the same volume of the material. For example, let us consider a sphere of radius r: The surface area of the sphere will be 4πr2 The volume of the sphere = 4/3(πr3) Therefore the surface area to the volume ratio will be 4πr2/{4/3(πr3)} = 3/r It means that the surface area to volume ration increases with the decrease in radius of the sphere and vice versa.
If the radius of a sphere is doubled, the surface area increases by (2)2 = 4 times, and the volume increases by (2)3 = 8 times.
No. The surface to volume ratio of a sphere is always smaller than that of a cube. This is because the sphere has the smallest surface area compared to its volume, while the cube has the largest surface area compared to its volume.