The density would be 25/500 =0.05 g/mL This is a totally unlikely result since the rock has roughly one twentieth the density of water!
The volume is still 100 ml: the shape does not affect the volume.
The water will rise by the volume of the brass: volume = mass/density = 129g / 8.56 g/ml ≈ 15.1 ml → final reading ≈ 50.0 ml + 15.1 ml = 65.1 ml
Only if it is water, which has a mass of 1gram per ml volume
Almost exactly 100.00 mL.
The volume of rubbing alcohol in a 500 ml bottle with a 70% concentration is 0.7 * 500 ml = 350 ml. Therefore, the volume of water in the bottle is 500 ml - 350 ml = 150 ml.
Strangely enough, it is 500 millilitres!
The volume of 500 grams of water is approximately 0.5 liters.
Porosity is calculated by dividing the volume of voids (pores) by the total volume. In this case, the volume of voids is the difference between the volume of water added and the volume left on top of the saturated soil (400 mL - 150 mL = 250 mL). The total volume is the sum of the dry soil volume and the water added (500 mL + 400 mL = 900 mL). Therefore, the porosity of the soil is 250 mL / 900 mL, which is approximately 0.28 or 28%.
To make a 500 dilution, add 1 part of the substance you are diluting to 499 parts of water. For example, if you have 1 mL of the substance, you would add 499 mL of water to make a total volume of 500 mL for the dilution.
if you are talking about water then 500 grams of water is 500 ml of water. I hope this is what you mean.
1 gram = 1 mL so;500 g = 500 mL34
To make a 500 ml solution of 3% H2O2 from a 50% solution, you would need to dilute the 50% solution with water. You would add 325 ml of water to 175 ml of the 50% H2O2 solution to achieve a final volume of 500 ml with a concentration of 3% H2O2.
Since there are 1,000 mL in one liter, there are 500 mL in 1/2 liter.
The volume of water is 118 mL, since the mass and volume of water are equivalent at room temperature.
the porosity is 50%
To prepare 500 ml of 1N HCl from 10N HCl, you need to dilute the 10N HCl with distilled water. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial concentration needed, C2 is the final concentration, and V2 is the final volume. In this case, the calculation would be 10 x V1 = 1 x 500. Solve for V1 to find the volume of 10N HCl needed, then add distilled water to make a total volume of 500 ml.