First off, a cube cannot be 5 x 6 x 9. In a cube, the lengths of all the sides are the same.
Volume of a cube = (length of side)3
What you are referring to is a rectangular parallelopiped or a cuboid. The volume of a cuboid is length x breath x height.
In the case, V = 5 x 6 x 9 = 270 cubic units
A cube has 6 sides. 54 / 6 = 9 square inches per side sqrt(9) = 3 (3 squared = 9) Therefore, each side of the cube is 3 inches. To find the cube's volume, you cube 3: 3 * 3 * 3 = 27 Therefore, the cube has a volume of 27 cubic inches.
Volume of cube = 6*6*6 cubic inches. If the box is h inches high, volume of the box = 8*9*h cubic inches. So 6*6*6 = 8*9*h so h = 6*6*6/(8*9) = 3 inches.
453
The reference cube has a volume of 9 units cubed and weighs 5 pounds and is worth 216 dollars.One unit cubed would weight 5/9 lbs and would be worth 216/9 or $24The other cube has a volume of 16 units cubed.Therefore it would weigh 16 * 5/9 or 8.88888 unitsThe cube would be worth 24 * 16 = $384
A cube has a volume of 729 in3. What is the surface area of the cube?
A cube has 6 sides. 54 / 6 = 9 square inches per side sqrt(9) = 3 (3 squared = 9) Therefore, each side of the cube is 3 inches. To find the cube's volume, you cube 3: 3 * 3 * 3 = 27 Therefore, the cube has a volume of 27 cubic inches.
Volume of cube = 6*6*6 cubic inches. If the box is h inches high, volume of the box = 8*9*h cubic inches. So 6*6*6 = 8*9*h so h = 6*6*6/(8*9) = 3 inches.
The volume of a cube with an edge of 9 cm is: 729 cm3
453
A cube would not have such dimensions but if you meant a cuboid then it is:- 5*12*9 = 540 cubic cm
The reference cube has a volume of 9 units cubed and weighs 5 pounds and is worth 216 dollars.One unit cubed would weight 5/9 lbs and would be worth 216/9 or $24The other cube has a volume of 16 units cubed.Therefore it would weigh 16 * 5/9 or 8.88888 unitsThe cube would be worth 24 * 16 = $384
Six.A cube has 6 faces, so it would have 6 flat surfaces
A cube has a volume of 729 in3. What is the surface area of the cube?
The volume of a cube is the cube of the length of one edge. (9 inches)3 = 729 cubic inches.
729 units3
The volume of a cube is the length of the side cubed, orV = s3V = 93V = 729 in3It is: 9*9*9 = 729 cubic inches
The 'capacity' (volume) of a cube with edges of 9 units is: 729 units3