Since a canister is a cylinder, we can use the formula for the volume of a cylinder, which is V = (pi)(r^2)(h), where pi = 3.14159..., r^2 is the radius squared, and h is the height of the cylinder. Your cylinder has a height of ten inches and a radius of five inches. V = (pi)(5in^2)(10in) = (pi)(25in^2)(10in) =785in^3. Note: The superscript and subscripts are not currently working.
V= 3.14r2hSubstitute the values...2503 in3 = 3.14 X 52 X h2503in3/3.14= 25 in2 h797.13 in3 = 25 in2 h797.13 in 3 / 25 in2 = h31.88 in = h
169.291m
The area is 16.25 units2
90 cubic inches.
Surface area excluding the bases: 20*pi*5 = 100*pi square inches
A cylinder has a volume equal to the area of its circular face multiplied by its height. Area of a circle is (pi)*r^2, where "r" is the radius of the circle. Since the diameter is twice the radius, the radius in this case is 1.25 inches. Area = (pi)*(1.25in)^2 = 4.9087in^2 This, multiplied by the height of the can, yields a volume of (5in)*(pi)*(1.25in)^2 = 24.5437in^3 or about 24.5 inches cubed.
Perpendicular height is 95.608 inches and slant height is 95.738 inches.
Since a canister is a cylinder, we can use the formula for the volume of a cylinder, which is V = (pi)(r^2)(h), where pi = 3.14159..., r^2 is the radius squared, and h is the height of the cylinder. Your cylinder has a height of ten inches and a radius of five inches. V = (pi)(5in^2)(10in) = (pi)(25in^2)(10in) =785in^3. Note: The superscript and subscripts are not currently working.
You did not give enough information to answer the question, but the formula is Volume=(Area of the base)•(Height) / 3
me its 5in diameter
what is the volume of the rectacgular solid 2in,5in,3in.
h= 1884/25*3.14 V=1884 r=5 h=236.63 in h= 1884/25*3.14 V=1884 r=5 h=236.63 in
It is: 5*3*6 = 90 cubic inches
V= 3.14r2hSubstitute the values...2503 in3 = 3.14 X 52 X h2503in3/3.14= 25 in2 h797.13 in3 = 25 in2 h797.13 in 3 / 25 in2 = h31.88 in = h
169.291m
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