The formula for the volume of a right cone (and pyramid) is 1/3 base x height, therefore the volume of this cone is :
Base = 3 x 3 x pi
Height = 9
Volume = 27 x pi, or roughly 84.8 units squared
Note: On a math test or quiz, you will lose marks for not saying units squared.
The volume of a right circular cone with a radius of 4mm and a height of 6mm equals 140.88mm3
r = 0.41702
A right circular cone with a base radius of 3 ft and a height of 9 ft has a volume of: 84.8 cubic feet.
V = (1/3) × (Π × r2 × h)Where, h = Height m = Slant Height V = Volume r = Radius of Base
Where slant height is 7ft and base radius is 4.5ft, the volume of a right circular cone will be 113.705 units cubed.
The volume of a right circular cone with a radius of 4mm and a height of 6mm equals 140.88mm3
r = 0.41702
Volume of the cylinder: pi*radius*radius*height
A right circular cone with a base radius of 3 ft and a height of 9 ft has a volume of: 84.8 cubic feet.
V = 7,943 ft3
A cylinder with a radius of 3 meters and a height of 5 meters has a volume of 141.37 cubic meters.
The volume is 47.12 cubic meters.
The volume is 141.37 cubic meters.
108m3
volume of a regular right circular cylinder is V=pi(r2)h since the radius is (a) then the height of the circular cylinder would be (2a) so the volume of the largest possible right circular cylinder is... V=2(pi)(r2)(a) with (pi) being 3.14159 with (r) being the radius of the circle on the top and bottom of the cylinder with (a) being the radius of the sphere
V = (1/3) × (Π × r2 × h)Where, h = Height m = Slant Height V = Volume r = Radius of Base
Where slant height is 7ft and base radius is 4.5ft, the volume of a right circular cone will be 113.705 units cubed.