Lets pretend that the Earth is a perfect sphere. Surface area of a sphere = 4(pi)(radius)^2. The radius of earth is 6378.1 km. Plug that into your equation and you'll get your answer.
A circle with a radius of 1.8 km has a circumference of 11.31 km
radius = 48/2 = 24 km
Radius = approx 6050 km, so diameter = 12100 km.
Where r is the radius of the Earth, and pi = 3.14 (2 decimal places). So, it's 4 thirds multiplied by pi multiplied by the cubed radius of the Earth (6378.1Km average)The best estimate for the Earth's volume is about 1083210000000 cubic km
The volume of this sphere is: 1,092,900,000,000 cubic km
The answer is Pi R2 The answer is Pi R2
It is: 4*pi*64002 square km
Jupiter is not a perfect sphere: it bulges out at its equator.The polar radius is 66854 kmThe equatorial radius is 71492 kmThe average radius is 69911 km.
If you want an approximate answer, we can assume the Earth and the Moon to be spheres, then go google for their radii, and plug that in the formula for volume of a sphere,V=(4/3)*pi*(radius)^3. Volume of Earth about 1.08321 x 10^12 km^3 Volume of Moon about 2.1958 x 10^10 km^3 The purpose of my answer was to explain how to calculate the volume not of just earth and moon, but any celestial object that can be approximated to a sphere, provided you know the radius. ps- I know the question is to tell the volume, not how to calculate it, but I thought the latter way of approaching the question would be more helpful!
The thickness of the inner core is 1,200 km. 1,200 km being the radius of the sphere known as the inner core.
Lets pretend that the Earth is a perfect sphere. Surface area of a sphere = 4(pi)(radius)^2. The radius of earth is 6378.1 km. Plug that into your equation and you'll get your answer.
The volume of the moon is approximately 2.195 x 10^10 cubic kilometers.
Jupiter is not a perfect sphere: it bulges out at its equator.The polar radius is 66854 kmThe equatorial radius is 71492 kmThe average radius is 69911 km.
1.083x10^21 m^3 (cubic meters) 3.826x10^22 ft^3 (cubic feet) 1.083x10^24 L (liters) Radius r of a sphere from V=4pir^3/3: | 6371 km (kilometers) | 3959 miles Edge length a of a cube from V=a^3: | 10 270 km (kilometers) | 6382 miles Welcome to WolframAlpha.com, enjoy. http://www.wolframalpha.com/input/?i=what+is+the+volume+of+earth
The Sun's total energy crosses a sphere with a radius of 149.6 million km at the distance of the Earth, and the area of that sphere is 2.812E17 square kilometres. From that the Earth intercepts a circular area with a radius of 6178 km, with an area of 1.2E8 square km. So the maximum possible proportion of the Sun's energy intercepted by the Earth is 1.2E8 / 2.18E17 which is 5.5E-10 or .000000055%.
The average radius of Mars is about 3,389.5 kilometers.