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What is the volume of a square based pyramid with base side lengths of 16 meters a slant height of 17 meters and a height of 15 meters?
V=1/3Bh This is the equation for volume of a pyramid.
V=(1/3)(16x16)(15) Substitute values. B is the area of the base, so 16x16.
V=(1/3)(256)(15) The area of the base was found.
V=(1/3)(3480) The height and base were multiplied.
V=1280 The whole product of those numbers was divided by three.
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What is the lateral area of a pyramid whose base is a square with sides measuring 16 meters and a slant height of 17 meters?
544 m2
What is the volume of a pyramid with a height of 3 centimeters and a square base with side lengths that measure 8 centimeters?
Volume of pyramid: 1/3*8squared*3 = 64 cubic cm
What are the side lengths of a square if its area is 81 meters squared?
The side lengths of a square if its area is 81 meters squared is: 9 meters.
What is the side length of a square with an area of 60 square meters?
The side lengths of a square with an area of 60 square meters is: 7.746 meters.
If a particular right square based pyramid has a volume of 63690 cubic meters and a height of thirty meters What is the number of meters in the length of the lateral height segment AB of a pyramid?
The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)
