Want this question answered?
Be notified when an answer is posted
If the object hsa sunk the volume is equal to the volume of water displaced If the tank is 50 cm high, the volume is 150x100x (36.2-30) = 93000 cubic centimeters
Its volume is: pi*0.202*2.5 = 1/10 times pi cubic meters
To tile a space that is 1m by 40cm, first convert the measurements to a common unit. 1m is equivalent to 100cm. So the space is 100cm by 40cm. To find the total area to be tiled, multiply the length by the width: 100cm x 40cm = 4000cm². Since each tile is 10cm x 10cm = 100cm², divide the total area by the area of each tile: 4000cm² ÷ 100cm² = 40 tiles. You would need 40 10cm square tiles to tile the space.
The volume depends on the radius also. You need this to complete the question.
Volume = pi*r2*h = 40715.04 cubic cm
The volume is 502,654.8cm3
Volume = (90 x 40 x 30) = 108,000 cm3 = 108 liters
40cm times 40cm times 40cm equals 64,000cm. The volume of the cube is 64,000cm cubed or 0.064m cubed.
100cm = 1M40cm = 0.4M = 4/10
48,000 cubic cm
It is a square with lengths of 10 cm
If the object hsa sunk the volume is equal to the volume of water displaced If the tank is 50 cm high, the volume is 150x100x (36.2-30) = 93000 cubic centimeters
Its volume is: pi*0.202*2.5 = 1/10 times pi cubic meters
To tile a space that is 1m by 40cm, first convert the measurements to a common unit. 1m is equivalent to 100cm. So the space is 100cm by 40cm. To find the total area to be tiled, multiply the length by the width: 100cm x 40cm = 4000cm². Since each tile is 10cm x 10cm = 100cm², divide the total area by the area of each tile: 4000cm² ÷ 100cm² = 40 tiles. You would need 40 10cm square tiles to tile the space.
The volume depends on the radius also. You need this to complete the question.
The volume of this cone is 37,699 cm3
1m = 100cm so 60cm x 40 cm x 40 cm = .6m x .4m x .4m = .096m^2