To calculate the volume of a tank, you multiply its length, width, and height. However, the height of the tank is not provided in your question. Assuming you have a height measurement, you can use the formula: Volume = Length × Width × Height. If the height is known, simply substitute the values into the formula to find the volume.
If the object hsa sunk the volume is equal to the volume of water displaced If the tank is 50 cm high, the volume is 150x100x (36.2-30) = 93000 cubic centimeters
1 metre = 100 centimetres Area = 100 x 40 = 4000 cm2 Area of each tile = 10x 10 = 100 cm2 Number of tiles required = 4000/100 = 40 tiles Alternatively, 10 tile lengths = 1 metre : 4 tile lengths = 40 cm Number of tiles required = 10 x 4 = 40
Its volume is: pi*0.202*2.5 = 1/10 times pi cubic meters
The volume depends on the radius also. You need this to complete the question.
Volume = pi*r2*h = 40715.04 cubic cm
The volume is 502,654.8cm3
Volume = (90 x 40 x 30) = 108,000 cm3 = 108 liters
40cm times 40cm times 40cm equals 64,000cm. The volume of the cube is 64,000cm cubed or 0.064m cubed.
100cm = 1M40cm = 0.4M = 4/10
It is a square with lengths of 10 cm
48,000 cubic cm
If the object hsa sunk the volume is equal to the volume of water displaced If the tank is 50 cm high, the volume is 150x100x (36.2-30) = 93000 cubic centimeters
1 metre = 100 centimetres Area = 100 x 40 = 4000 cm2 Area of each tile = 10x 10 = 100 cm2 Number of tiles required = 4000/100 = 40 tiles Alternatively, 10 tile lengths = 1 metre : 4 tile lengths = 40 cm Number of tiles required = 10 x 4 = 40
Its volume is: pi*0.202*2.5 = 1/10 times pi cubic meters
The volume depends on the radius also. You need this to complete the question.
1m = 100cm so 60cm x 40 cm x 40 cm = .6m x .4m x .4m = .096m^2
The volume of this cone is 37,699 cm3