It is 36 cubic inches.
The height of a triangular based pyramid is given by h=2V/(bxl). V is its volume, b its base and l its length.
The formula for finding the volume for a triangular pyramid is half base x height x length. A triangular pyramid has four faces.
If the base length is 6 inches then the base area will be 9*sqrt(3) = 15.6 cm2, which rounds to 16, not 15. So some of the information provided is patently incorrect and therefore the question has no sensible answer.
Volume = 50 in3
Use the Pythagorean theorem: a^2 + b^2 = c^2 a = sqrt (c^2 - b^2) Where: a=the height (pyramid height from base to peak) b=the base length c = the hypotenuse (slant) length
The height of a triangular based pyramid is given by h=2V/(bxl). V is its volume, b its base and l its length.
The formula for finding the volume for a triangular pyramid is half base x height x length. A triangular pyramid has four faces.
72
If the base length is 6 inches then the base area will be 9*sqrt(3) = 15.6 cm2, which rounds to 16, not 15. So some of the information provided is patently incorrect and therefore the question has no sensible answer.
Volume = 50 in3
Use the Pythagorean theorem: a^2 + b^2 = c^2 a = sqrt (c^2 - b^2) Where: a=the height (pyramid height from base to peak) b=the base length c = the hypotenuse (slant) length
There is not enough information to give an answer.
You did not give the height of the pyramid and 16 cm is not an area, but the area of the face would be one half the face height of the side of the pyramid times the length of the base side.
To calculate the surface area of a square pyramid, you need to find the area of the base (which is a square) and the area of the four triangular faces. The formula for the surface area of a square pyramid is SA = s^2 + 2sl, where s is the side length of the base and l is the slant height. In this case, with a base side length of 8 inches and a slant height of 15 inches, the surface area would be SA = 8^2 + 2(8)(15) = 64 + 240 = 304 square inches.
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
The Pyramid of Khufu, also known as the Great Pyramid of Giza, has a triangular face with a base length of approximately 230.4 meters and a height of around 146.6 meters. The area of one triangular face can be calculated using the formula for the area of a triangle: ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ). This results in an area of about 16,900 square meters for each triangular face.
The lateral surface area of a square pyramid can be calculated using the formula: ( \text{Lateral Area} = 2 \times \text{base length} \times \text{slant height} ). Here, the base length refers to the length of one side of the square base, and the slant height is the height of the triangular face from the base to the apex of the pyramid. To find the total lateral area, simply plug in the values for the base length and slant height into the formula.