well if you divide 5.00 g by 1.48 you will get the answer of 3.38.
d = m/v therefore v=m/d * v = 2500.0 grams / 10.5 g/cm cubed * v = 238.1 cm cubed (one sig dig) * "The volume of silver metal that will have a mass of 2500.0 grams is 238.1 cm cubed."
Density = 11340 kgm-3 = 11.340 gcm-3 Then Volume = Mass/Density = 178.96 g/11.34 gcm-3 = 15.781 cm3 approx and Thickness = Volume/(Length1 * Length2) = 15.781/(6.15 * 4.6) = 44.304 cm.
The GCM is infinite.
GCM(18, 42) = 6
17.16
Density = Mass/Volume = 57.2g/11 cm3 = 5.2 gcm-3
well if you divide 5.00 g by 1.48 you will get the answer of 3.38.
217.898135 cubic meters == mass per cubic meter is 917 grams so 217.898 * 917 = 199812.47 grams = 199.81 Kg
d = m/v therefore v=m/d * v = 2500.0 grams / 10.5 g/cm cubed * v = 238.1 cm cubed (one sig dig) * "The volume of silver metal that will have a mass of 2500.0 grams is 238.1 cm cubed."
Density = Mass/Volume = 112/24 gcm-3 = 4.667 gcm-3
Density = mass/volume = 18/25 gcm-3 = 0.72 gcm-3
Density = 11340 kgm-3 = 11.340 gcm-3 Then Volume = Mass/Density = 178.96 g/11.34 gcm-3 = 15.781 cm3 approx and Thickness = Volume/(Length1 * Length2) = 15.781/(6.15 * 4.6) = 44.304 cm.
Cannot say. Edge length is too few information. You need to know the volume of the platinum, i.e. length, width, and depth. To do-it-yourself, measure the platinum. Give all lengths in cm. Multiply the lengths by each other. You get volume in cm cubed. Multiply the volume by 21,4. You get a number. That is the mass of the platinum in grams.
The volume of the substance can be found by dividing the mass by the density. In this case, the volume is 554 grams / 3.1 grams per cubic centimeter, which equals 178.71 cubic centimeters.
Cylinder Volume = (pi) *(radius2)*(height) Cylinder volume = (3.1416)*(22)*(80) Cylinder volume = 1005.312 cm Density = Mass / Volume 0.0045 gcm = Mass / 1005.312 cm Mass = 0.0045 gcm * 1005.312 cm Mass = 4.523904 g
Density = mass/volume. Density(A) = 40.2/5.7 = 7.05 gcm-3 Density(B) = 42.0/6.3 = 6.67 gcm-3 So B is less dense.