If the tank is a cube, and each edge is 500mm long, then the volume of the tank is50cm x 50cm x 50cm = 125,000 cm3 = 125 litres.
Volume = pi*r2*h = pi*202*250 cm3 = 314,159.3 cm3 = 314.16 litres.
density = mass ÷ volume= 20 g ÷ 12 cm3≈ 1.67 g/cm3
density = mass ÷ volume = 30 g ÷ 10 cm3 = 3 g/cm3
The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3The volume of the aquiarm - whatever that might be - is 720,000 cm3 or 0.72 m3
The volume of the tank is (81 x 32 x 39) = 101,088 cm3 = 101.088 liters = 26.705 gallons (rounded)That's the volume of the tank up to the rim. We have no way of knowinghow much water may be in it.
Volume = (90 x 40 x 30) = 108,000 cm3 = 108 liters
The volume is: 301.6 cm3
Use volume which is cm3 ? x ? x ? Length Width Depth
Volume = pi*r2*h = 92.76 cm3 Volume = pi*r2*h = 92.76 cm3 Volume = pi*r2*h = 92.76 cm3 Volume = pi*r2*h = 92.76 cm3
You did not specify the dimensional units of the tank. I am going to assume inches. A 70 in x 55 in x 25 in tank has a volume of 96,250 in3. Multiply that by 2.543 cm3 in-3 and you get 1,577,254.91 cm3. Divide that by 1,000 cm3 L-1 and you get 1,577.25491 L.
If the tank is a cube, and each edge is 500mm long, then the volume of the tank is50cm x 50cm x 50cm = 125,000 cm3 = 125 litres.
The volume is already stated. 75 cm3
Volume = pi*r2*h = pi*202*250 cm3 = 314,159.3 cm3 = 314.16 litres.
69300 cm3 divided by 1163 cm3 = 59.587. 59 books.
The density of the substance can be calculated by dividing the mass (31 g) by the volume (68 cm3). So, density = mass/volume = 31 g / 68 cm3 ≈ 0.46 g/cm3.
None. Cubic cm3 is a measure of "volume" in 9-dimensional hyperspace whereas cm3 is a measure of volume in the normal 3-dimensional space which we inhabit.