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Calculating the weight of a cylinder?
The mass of a cylinder would be the volume times the density of the material it is made of. Therefore, where m = mass, r = radius, h = height, and ρ = density: m = πr2hρ The mass would correspond to the weight 1:1 on Earth and that would be the final answer. If the object is under a different gravity situation, the weight will need to be adjusted accordingly.
What do you use to measure mass and weight?
Newton's Law F = m * a Force is a product of mass and acceleration Weight is a special case of Newton's Laws W = m * g Weight is a product of mass and the acceleration due to gravity. Weight, W, is in Newtons (N) mass, m, is in kilograms (kg) g = 9.81 m/s²
If we have a fabric piece of 10 cm by 10 cm how to calculate its GSM?
1m = 100 cm 1 sq m = 1 m × 1 m = 100 cm × 100 cm = 10,000 cm² 10 cm × 10 cm = 100 cm² → 1 sq m ÷ 100 cm² 10,000 cm² ÷ 100 cm² = 100 → weight the piece of cloth that is 10 cm by 10 cm in grams and multiple it by 100 to find out how many grams a piece of the same cloth which is 1 m by 1 m (1 square metre in area) weighs. You then know its gsm.
What is 1 plus m?
1 + m is the simplest expression you can make for this problem.
What is larger 1 m or 1 cm?
1 m
What is The kinetic energy of a 25 gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
What is The kinetic energy of a 25-gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
A 1N weight has a kinetic energy of 1 J when the speed is?
E = ½mV² → V = √(2E/m) The mass of a 1 N weight (on earth) is 1/9.8 kg Ergo, V = √(2*1/(1/9.8)) = √19.6 = 4.43 m/s
How much is .15 grams?
It's easy to think about 1 gram as equal to 1 M&M so 15 grams would equal the weight of 15 M&M's -- approximately.
What is the weight of a 32 millimeter steel rod of 1 meter?
6.320kg/m
What is the weight of 1m3 of cement?
The weight of 1 cubic meter (m^3) of cement is typically around 1440 kg.
Is 69kg a good weight for a 13 year old?
A lot depends on your height. If you have 1 m. 69 cm. then the weight is perfect for you.
How many Weight Watchers points in peanut m and ms?
1 bag is 6 Points
What is the weight of a m and m?
about 6.3 grams
What is the formula to calculate weight?
Weight=m*g m=mass g=acceleration of gravity
What is the weight of a cubic meter?
mass = density * volume weight = mass * acceleration due to gravity W = (2400 kg/m^3)*(1 m^3)*(9.8 m/s^2) = 23520 Newtons convert to pounds 23520 Newtons = 5287.5 lbs (note 1 lb is approximately 4.448 Newtons)
Weight of 32 mm dia steel bar per 1 meter?
6.314 kg/m
