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What is the weight of an iron rod that is 12 inches long 3 inches wide and 5 inches tall?
To find the weight of the iron rod, first calculate its volume by multiplying the dimensions: volume = length × width × height = 12 in × 3 in × 5 in = 180 cubic inches. The density of iron is approximately 490 pounds per cubic foot, which converts to about 0.284 pounds per cubic inch. Therefore, the weight of the rod is approximately 180 in³ × 0.284 lb/in³ = 51.12 pounds.
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