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How do you get area of an octagon?
The easiest method is to split the octagon up into triangles and sum the areas of the triangles.
What is the hardest math sum in the world?
what is the percentage of the gods existence in this world ? its 23846.63542
What is the hardest sum in the world?
658956235896956828945625602472389456947874956234756234785692347652847 x 752605078465078560765347806598945997876576235323567623567652856895369 / 762045762580607025760234785624758069375978635789656963957863974563956 = poo
What is the sum of all integers not greater than 10000 that are not divisible by 7?
This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858
What are 3 odd integers whose sum is 141?
sum means numbers which add up to 141 41 is an obvious one which leaves you with 100 simplest thing would to be divide 100 by 2 but that gives 50 which is an even number so use 49 and 51. 41 + 49 + 51 = 141 Note, these aren't the only 3 odd numbers which sum to 141, that just seemed the easiest way to work it out to me.
