Assume the expression is 2x + 10y = 20.
x-intercept occurs where y = 0.
y-intercept occurs where x = 0.
Let's work on each part of the problem:
X-interceptLet y = 0. Then:
2x + 10(0) = 20
2x = 20
x = 20/2
x = 10
So the x-intercept is (10,0)
Y-interceptLet x = 0. Then:
2(0) + 10y = 20
10y = 20
y = 20/10
y = 2
So the y-intercept is (0,2).
y = -2x+10
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
4x+2y = 20 2y = -4x+20 y = -2x+10
12
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
y = -2x+10
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
4x+2y = 20 2y = -4x+20 y = -2x+10
8
12
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
-2
10
8
The y-intercept equals 0.
The slope will be the same but the y intercept will change:- y -14 = - 2(x - 10) y -14 = -2x +20 y = -2x +20 +14 y = -2x +34