y = f(x) = (x-5)2. At x = 5, the y value is zero, so the point (5,0).
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The x-intercept will be the point (x,0) The y-intercept will be the point (0,y) Since you have two points, you can calculate the slope (which is m): m = (y - 0) / (0 - x) b is the y-intercept: b = y so, f(x) = mx + b
in general, the y-intercept of the function f(X)= axb^x is the point__.
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y = f(x) = (x-5)2. At x = 5, the y value is zero, so the point (5,0).
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What_is_the_area_bounded_by_the_graphs_of_fx_and_gx_where_fx_equals_xcubed_and_gx_equals_2x-xsquared
The properties and conditions of FX to satisfy such that the fx equals its fourier seasons, should be of the fans, and the ones that actually watch the awseome series that are on FX. Lots of people are huge fans of FX and really get destroyed when there is no satisfaction of the fourier seasons.
The population of BAKED FX is 15.
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The x-intercept will be the point (x,0) The y-intercept will be the point (0,y) Since you have two points, you can calculate the slope (which is m): m = (y - 0) / (0 - x) b is the y-intercept: b = y so, f(x) = mx + b
fx=5x1 / 9
fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide