x^2 - 4 = 0
What you have to recognise is that the constant '4' is a 'squared number.
4 = 2^2
So we can write
x^2 - 2^2 = 0
Next remember that two squared terms with negative between then, factors.
Hence
x^2 - 2^2 = 0
=>
( x - 2)(x + 2) = 0
NB Note the plus (+) sign in the second bracket.
Hence
x - 2 = 0
x = 2
&
x + 2 = 0
x = -2
So 'x' can take two values, they are '(+)2, & -2'.
NB Note that two squared terms with a plus(+) between then , does NOT factor. e.g. the Pythagorean equation. c^2 = a^2 + b^2
X = 5
The value of x would be 0
y = 6
It is not possible to be certain. If x >= 0 then abs(x) = x if x < 0 then abs(x) = -x
well 5x2=10 and anything x 0=0 so x=0 because 10x0=0
X = 5
The value of x would be 0
y = 6
The value is 1 if (x, y) = (4, 3) and 0 otherwise.
It is not possible to be certain. If x >= 0 then abs(x) = x if x < 0 then abs(x) = -x
well 5x2=10 and anything x 0=0 so x=0 because 10x0=0
here for least value X=2,y=3hence 2(3)-3(2)=0=0
That is how the absolute value is defined. For x < 0 the value of x is negative (by definition). Therefore, the value of negative x is positive (negative of a negative). So abs(x) = -x when x < 0
There is no answer to this (for any value of x) That's because x-x = 0 So x-x-7 is always -7, and never 0
The value of x is 7
No.
0 By the multiplication property of 0, any number multiplied by 0 equals 0