In order to answer that, we need to know the relationship between 'x' and 'y',
which you haven't described in your question.
Better answer: 'x' is never equal to 8 at the y-intercept. The y-intercept only
depends on the relationship between 'x' and 'y'. After that, 'x' is always zero
at the y-intercept.
11
X intercept = -4 Y intercept = 2
y = -x + 8
8
-8
11
Set y = 0 -x = 8 so that x = -8 is the x-intercept. Set x = 0 2y = 8 so that y = 4 is the y-intercept.
x is the same, so 8 y is undefined
Add 8 to the x value, so f.e. If x=4, the y intercept = 4+8 =12 No, the y intercept is the value of y when the value of x = 0, so the y intercept of the equation is 8. In the general form y = mx + b, b will always be the y intercept.
-11
The graph of [ x=8 ] is a vertical line through the point 8 on the x-axis. It never touches the y-axis, and has no y-intercept.
-4x + y = 8At the x-intercept, 'y' is zero.-4x = 8-x = 2x = -2At the y-intercept, 'x' is zero.y = 8
y=x+8 is a linear equation. Y is the Y point on a graph, X is the slope, and 8 is the y intercept
X intercept = -4 Y intercept = 2
y = -x + 8
-6
8