-1
y=mx+b; m=slope & b=y intercept. Therefore y=-2x+(-3) or y=-2x-3.
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
2x - 3y = 0 y = 2x/3 (at x-intercepts, y = 0) therefore, 2x/3 = 0 x = 0. x = 0 is the x- intercept
2x-3y = 4 -3y = -2x+4 y = 2/3x-4/3 So the slope is 2/3 and the intercept is -4/3
-1
x-intercept: 6; y-intercept: 3
y=mx+b; m=slope & b=y intercept. Therefore y=-2x+(-3) or y=-2x-3.
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
2x - 3y = 0 y = 2x/3 (at x-intercepts, y = 0) therefore, 2x/3 = 0 x = 0. x = 0 is the x- intercept
2x-3y = 4 -3y = -2x+4 y = 2/3x-4/3 So the slope is 2/3 and the intercept is -4/3
1
5
x intercept: (1.5, 0) y intercept: (0, 3)
-4
The x-interceptin is where the graph crosses the y-axis, which is where y equals 0: 0 = 2x + 3 2x = -3 x = -3/2 So the x intercept is as x = -3/2 (and y = 0).
2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3