9x + 3y = -54
3y = -9x - 54
y = -(3x + 18)
Therefore, the y-intercept of this equation is y=-18.
-7x+9y = 54 9y = 7x+54 y = 7/9x+6 which is now in slope-intercept form
Since there are no given triplets, none of them!
x/3-y/4 = 0 => multiply all terms by 12 => 4x-3y = 0 x/2+3y/10 = 27/5 => multiply all terms by 10 => 5x+3y = 54 4x-3y = 0 5x+3y = 54 Add both equations together which will eliminate 3y: 9x = 54 Divide both sides by 9: x = 6 Substituting the value of x into 5x+3y = 54 and 4x-3y = 0 gives y a value of 8. Therefore: x = 6 and y = 8
54 + 560 + 90 = 704
93
The list of choices that accompanies the question is really short.2x + 3y + 6z = 54At the y-intercept, 'x' and 'z' are zero.3y = 54y = 18
-7x+9y = 54 9y = 7x+54 y = 7/9x+6 which is now in slope-intercept form
The numbers 3y times 18 equals 54. This is taught in math.
Since there are no given triplets, none of them!
x/3-y/4 = 0 => multiply all terms by 12 => 4x-3y = 0 x/2+3y/10 = 27/5 => multiply all terms by 10 => 5x+3y = 54 4x-3y = 0 5x+3y = 54 Add both equations together which will eliminate 3y: 9x = 54 Divide both sides by 9: x = 6 Substituting the value of x into 5x+3y = 54 and 4x-3y = 0 gives y a value of 8. Therefore: x = 6 and y = 8
It is: 126 plus 54 = 180
54 + 560 + 90 = 704
346
93
54
The answer is 613.
Simultaneous equations: x/3 -y/4 = 0 and x/2 +3y/10 = 27/5 Multiply all terms in the 1st by 12 and in the 2nd equation by 10 So: 4x -3y = 0 and 5x +3y = 54 Add both equations together: 9x = 54 => x = 6 Solutions by substitution: x = 6 and y = 8