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If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
Presumably the dimension of 2 units is the thickness of the boards in which case 3 boards are needed because 6*8 = 48 and 144/48 = 3
x^(2-x-6)/x^(2-4) x^(-4-x)/x^-2(x^-2)*(x^(-2-6))= x^(-2-x)
2 x 3 is 6 / 6 x 6 = 36
-6 X -2 (-1)6X(-1)2 (-1)(-1)12 12