NI(NO3)3+pbbr4nibr3+pb(no3)4
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The balanced chemical equation for the reaction between cobalt (II) bromide (CoBr2) and lead nitrate (Pb(NO3)2) is: CoBr2 + Pb(NO3)2 → Co(NO3)2 + PbBr2 This equation is balanced with 1 molecule of cobalt (II) bromide reacting with 1 molecule of lead nitrate to produce 1 molecule of cobalt (II) nitrate and 1 molecule of lead (II) bromide.
The binary compound formula for plumbic bromide is PbBr2.
PbBr4 and PbI4 are unstable due to the high oxidation state of lead (Pb) in these compounds, which makes them prone to reduction. Lead typically exhibits stable oxidation states of +2 and +4, but in these tetrahalides, the +4 state is less stable due to the larger size and lower electronegativity of bromine and iodine, which can lead to bond weakening. Additionally, the formation of stable lower oxidation state compounds, such as PbBr2 or PbI2, is thermodynamically favored, contributing to the instability of PbBr4 and PbI4.
The chemical formula for lead (IV) bromide is PbBr4. It is composed of one lead (Pb) ion with a charge of +4, and four bromine (Br) ions with a charge of -1 each.
Lead(IV) bromide (PbBr₄) consists of one lead atom and four bromine atoms. Therefore, in a single formula unit of PbBr₄, there are a total of 5 atoms (1 Pb + 4 Br).
The chemical formula for Lead (II) Bromide is - PbBr2
It's Lead (IV)Bromide We use roman numerals when it's a transition metal + nonmetal