The number 1 010 101 is equivalent to 85 in decimal form. This can be calculated by converting each digit in the binary number to its decimal equivalent and adding them together. In this case, 12^6 + 02^5 + 12^4 + 02^3 + 12^2 + 02^1 + 1*2^0 = 64 + 0 + 16 + 0 + 4 + 0 + 1 = 85.
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Oh, dude, that number is 1,010,101. It's like a mix of 1s and 0s just hanging out together. It's technically a binary number, but like, who really cares about that, right? Just a bunch of ones and zeros doing their thing.
To a decimal base "1,010,101" is One million ten thousand one hundred and one.
To a binary base "1010101" is the decimal number Eighty five.
To convert a binary number to an octal number, you need to know how an octal number is represented in binary. It is like this: 0 = 000 4 = 100 1 = 001 5 = 101 2 = 010 6 = 110 3 = 011 7 = 111 As you can see, an octal number consists of 3 'bits' (either a 0 of a 1). Now, to convert a binary number to an octal number, you first have to group the binary digits into groups of 3 bits (starting from the right). Then, you convert every group of bits into octal numbers. This way you get your binary number into an octal one. For example: (1010100111010010)2 We group them into groups of 3 bits, starting from the right. 1 010 100 111 010 010 As you see, we have a single digit left. We must add 0's to make it a group of 3 bits. 001 010 100 111 010 010 Then we convert every group into an octal number, according to the table above. 001 = 1 010 = 2 100 = 4 111 = 7 010 = 2 010 = 2 And in this way, you converted a binary number into an octal one. (1010100111010010)2 = (124722)8
1 x 101 = 101 It's the only solution because 101 is a prime number (only divisible by "1" and itself).
No, 101 is not a composite number. It is a prime number because it is only divisible by 1 and itself.
Two: 1 and 101 (101 is a prime number).
It is: 101/100 = 1 and 1/100