108, 162, 216 & 270
x + (x+1) + (x+2) = 108 3x + 3 = 108 3x = 105 x = 35 35,36,37
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
How about 3*4*9 = 108 as one example
30.bec 24+26+28+30=108/4=27
Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
-106, -107, -108
108, 162, 216 & 270
x + (x+1) + (x+2) = 108 3x + 3 = 108 3x = 105 x = 35 35,36,37
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
108 109 110 111 112 113 114
How about 3*4*9 = 108 as one example
30.bec 24+26+28+30=108/4=27
Sum of five consecutive even numbers is 540. So the middle one is 540/5 = 108. The other four are 108-4, 108-2, 108+2 and 108+4. So the largest is 108+4 = 112 degrees.
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
108 117 126 135 144 153 and 162
24 + 26 + 28 + 30 = 108