2x + 2
2x + 5 = -3 2x = -8 x = -8/2 x = -4
2
The statement "Twice the quantity of a number plus two is greater than the number plus five" can be expressed mathematically as (2x + 2 > x + 5), where (x) is the number. To solve this inequality, we can subtract (x) from both sides, resulting in (x + 2 > 5). Further simplifying gives (x > 3). Thus, the solution indicates that the number must be greater than 3.
x + x + 1 + x + 2 + x + 3 = -144x + 6 = 144x = 8x = 2
The equation 5X plus 4X-2-2 times2 X-1 plus 3 X plus 2 equals 2. This is a math problem.
x + 2x
2x + 2 > x + 5
n>3 2x + 2 > x + 5
2x + 5 = -3 2x = -8 x = -8/2 x = -4
2
I divided it by 2 twice, then by 3 twice, then by 5. 2 x 2 x 3 x 3 x 5 = 180
x + x + 1 + x + 2 + x + 3 = -144x + 6 = 144x = 8x = 2
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
(x-2)(x^2+3)
Generally, "twice" means double. So, twice X is equal to X plus X. Twice four is eight. simmisinghsaini's answer- But however, doesn't it mean to divide when we have to translate algebraic expressions?
x^3+x^2+2x = x(x^2+x+2)
The equation 5X plus 4X-2-2 times2 X-1 plus 3 X plus 2 equals 2. This is a math problem.