the way i figure it is, when multiplying fractions go top #'s --2x10= 20
bottom #s--5x11= 55
these #s can be reduced...
by the" common divider" ?? (5)
20/5=4
55/5=11
answer=4/11
there is five-fifths in one. ten-fifths in two, so there are five two-fifths in two.
Ten fifths = two and no matter what you try, it will not be a proper fraction!
50 of them because 50/5 = 10
12 and 4 fifths
two fifths of five sevenths is ten thirty fifths. Multiply the numerator and the denominators.
two elevenths
No ten twenty-fifths is the same as two fifths
With fractions, "of" means to multiply them. 2/5 * 4/11 = 8/55
there is five-fifths in one. ten-fifths in two, so there are five two-fifths in two.
Ten fifths = two and no matter what you try, it will not be a proper fraction!
Expressed as a proper fraction in its simplest form, 4/5 x 2/11 = 8/55 or eight fifty-fifths.
Four fifths.
one fifth of ten is the same as 10/5 which is the same as 2 so two fifths of 10 is twice what one fifth would be. Therefore 2 fifths of ten is 4.
50 of them because 50/5 = 10
25
400
Oh, dude, let me break it down for you. So, if you have 4 and you're trying to fit in two fifths, you just divide 4 by 2/5. That's like multiplying by the reciprocal, which gives you 10. So, there are 10 two fifths in 4. Easy peasy, lemon squeezy.