To calculate the weight of a rolled steel with given dimensions, we need the density of the steel. Assuming a typical density of 7850 kg/m³, the weight can be calculated as follows: the volume of the rolled steel is (π * radius² * height) - (π * (radius - thickness)² * height). Substituting the values, the weight would be (π * (2 feet)² * 12 feet) - (π * (2 feet - 1/4 inch)² * 12 feet), which equals approximately 19,347 pounds.
2 square feet.
Multiply 11 and 2 twelfths by 12 and 11 twelfths. 11 2/12 X 12 11/12 = 134/12 X 155/12 = 144 17/72 square feet. If you are dealing with floor covering then the width is usually sold in 12 feet units and you would multiply the width 12 feet times the length of practically 13 feet, which is 156 square feet.
24 inches is 2 feet long and a foot is about the size of a grown man's foot.there are 12 inches in a foot so therefore it is 2 feet
Volume = Length*Depth*Height = 2*4*1.5 = 12 cubic feet
2(12*12+8*12+8*12) =2(144+96+96) =2*336 =672
3 x 2 x 2 = 12 cubic feet
40 board feet
3 x 2 x 2 = 12 cubic feet
2 to 5 feet long
12 ft3
To calculate the weight of a rolled steel with given dimensions, we need the density of the steel. Assuming a typical density of 7850 kg/m³, the weight can be calculated as follows: the volume of the rolled steel is (π * radius² * height) - (π * (radius - thickness)² * height). Substituting the values, the weight would be (π * (2 feet)² * 12 feet) - (π * (2 feet - 1/4 inch)² * 12 feet), which equals approximately 19,347 pounds.
it is 12 inches. 3 feet is a yard.it's about the length of 2 dollar bills.A foot (plural: feet) is 12 inches or about 30 cm.
Their wingspan is 6 feet, their weight is 2.5 l. b. s.
1 foot = 12 inches. So, 26.3 feet = 26.3 x 12 = 315.6 inches.
about as big as 10 feet. just kidding 2 feet.
2 square feet.