equation works for n = 0 and n = 1 as factors are n and n - 1
Previous poster was very wrong, 5n-3=17 5n=20 n=4
Without an equality sign the given expression is not an equation.
Without an equality sign it is not an equation. But if: 6n = 216 Then: n = 36
n = 9
Well the equation is: 6CO2 + 6H2O + -s-u-n-l-i-g-h-t--> C6H12O6 + 6O2.
It is an equation: n - 9 = 9It is an equation: n - 9 = 9It is an equation: n - 9 = 9It is an equation: n - 9 = 9
n n n n n n n n n n n n n n n o o o o o o o o o o o o o t t t t t t t t t t t h h h h h h h h h h h h h h i i i i i i i i i i n n n n n n n n n n g g g g g g gg g g g g g g g gg gg g
N(h)4hc(o)3 = nh3 + h2o + co2
n n n n n n n n n n n n n n n o o o o o o o o o o o o o t t t t t t t t t t t h h h h h h h h h h h h h h i i i i i i i i i i n n n n n n n n n n g g g g g g gg g g g g g g g gg gg g
Energy in case of matter is E = m c^2 In case of photon energy E = h n. m - mass , c - velocity of light h - planck's constant and n - frequency of radiation
Use this equation M.(H2O)m+n = M.(H2O)m-1OH +(n-1) + H+
equation works for n = 0 and n = 1 as factors are n and n - 1
The Lewis structure for HNNN can be represented as N≡N-H. Each nitrogen atom is bonded to the adjacent nitrogen atom through a triple bond (denoted by ≡) and one nitrogen atom is bonded to a hydrogen atom.
It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15
multiplication is point to point and convolustion is point to multi-point ex multiplication-- s[n]=x[n].h[n] s[0]=[x[0].h[0] s[1]=[x[1].h[1] s[2]=[x[2].h[2] . . . .. s[n-1]=[x[n-1].h[n-1] convollustion s[n]=x[n]*h[n] s[0]=[x[0].h[0]+x[0].h[1]+x[0].h[2]+.......+x[0].h[n-1] s[1]=[x[1].h[0]+x[1].h[1]+x[1].h[2]+.......+x[1].h[n-1] s[2]=[x[2].h[2]+x[2].h[1]+x[2].h[2]+.......+x[2].h[n-1] . . . s[n-1]=[x[n-1].h[0]+x[n-1].h[1]+x[n-1].h[2]+.......+x[n-1].h[n-1].
Previous poster was very wrong, 5n-3=17 5n=20 n=4