3 = 1 x 3 5 = 1 x 5 7 = 1 x 7 GCF = 1
1 x 1 x 175 1 x 5 x 35 1 x 7 x 25 5 x 5 x 7
1 x 35, 5 x 7, 7 x 5, 35 x 1
75 x (1/7)5 1/7 = 7-1 So, (1/7)5 = (7-1)5 = 7-5 Replacing this in the original expression gives, 75 x 7-5 = 7(5 -5) = 70 = 1 Alternatively, (1/7)5 = 15/75 = 1/75 we could then write, 75 x 1/75 = 1
35 = 1 x 35, 5 x 7, 7 x 5, 35 x 1
3 = 1 x 3 5 = 1 x 5 7 = 1 x 7 GCF = 1
The factors of 35 are 1, 5, 7, and 35. The factor pairs of 35 are 1 x 35 and 5 x 7.1, 5, 7, 35.1 x 35, 5 x 7, 7 x 5, 35 x 1.1, 5, 7, 351,5,7,35
1 x 1 x 175 1 x 5 x 35 1 x 7 x 25 5 x 5 x 7
1 x 35, 5 x 7, 7 x 5, 35 x 1.
1 x 35, 5 x 7, 7 x 5, 35 x 1
1 x 35, 5 x 7, 7 x 5, 35 x 1
1 x 35, 5 x 7, 7 x 5, 35 x 1
3 x 5 x 7 x 7 x 13 or 3^1 x 5^1 x 7^2 x 13^1
7
1 x 35, 5 x 7, 7 x 5, 35 x 1
1 x 35, 5 x 7, 7 x 5, 35 x 1
1 x 35, 5 x 7, 7 x 5, 35 x 1