x2 + 4x = 0 ⇒ x(x + 4) = 0 ⇒ x = 0 or x = -4
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
x-intercept of y equals -4x plus 4 y = -4x + 4 0 = -4x + 4 -4 = -4x 1 = x So 1 is the x-intercept
x^2+4x=0 x(x+4)=0 x=0 and x+4=0 x=0 and x=-4
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
x = -½
x2 + 4x = 0 ⇒ x(x + 4) = 0 ⇒ x = 0 or x = -4
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
x-intercept of y equals -4x plus 4 y = -4x + 4 0 = -4x + 4 -4 = -4x 1 = x So 1 is the x-intercept
x^2+4x=0 x(x+4)=0 x=0 and x+4=0 x=0 and x=-4
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
4x+7=9x+7 -5x=0 x=0
y = -4x + 4 x intercept is where y = 0 0 = -4x +4 4x = 4 x = 1
4(x + 1) = 0.
8 + 4x - x = 8 3x = 8 - 8 x = 0
16x2 + 8x + 1 = 0 : This factorises to (4x + 1)(4x + 1) = 0 When 4x + 1 = 0 then 4x = -1 : x = -1/4.
4x + 3y=9 x=0 y=3